v=35v^2

Solution for v=35v^2 equation:

v=35v^2

We move all terms to the left:

v-(35v^2)=0

determiningTheFunctionDomain
-35v^2+v=0

a = -35; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-35)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-35}=\frac{-2}{-70}
=1/35
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-35}=\frac{0}{-70}
=0
$